Issues with hg update -C and bookmarks
Sean Farley
sean at farley.io
Tue Jul 14 17:28:36 UTC 2015
Marc Strapetz <marc.strapetz at syntevo.com> writes:
> With the following setup:
>
> $ hg init
> $ touch x
> $ hg commit -A "initial import"
> $ touch y
> $ hg commit -A -m "y added"
> $ hg checkout 0
> $ touch z
> $ hg commit -A -m "z added"
> $ hg up 1
> $ hg bookmark bm
>
> There will be default with two diverged heads at r1 and r2 and a
> bookmark on r1.
>
> $ hg summary
> parent: 1:4009599f6088
> y added
> branch: default
> bookmarks: *bm
> ...
>
> Starting from this setup, following behavior is rather unexpected to me:
>
> (1) hg update -C . will loose the active bookmark
>
> $ hg update -C .
> $ hg summary
> parent: 1:4009599f6088
> y added
> branch: default
> bookmarks: bm
> commit: (clean)
> update: 1 new changesets, 2 branch heads (merge)
>
> I would expect to see bookmark "*bm" still active.
>
> (2) hg upgdate -C checks out r2 (expected), but leaves bookmark bm
> active (unexpected)
>
> $ hg update -C
> $ hg summary
> parent: 2:eb990d6c7e06 tip
> z added
> branch: default
> commit: (clean)
> update: 1 new changesets, 2 branch heads (merge)
>
> $ hg bookmarks
> * bm 1:4009599f6088
>
> I would probably expect that bookmark "bm" isn't active anymore. What's
> the meaning of an active bookmark which is not checked out?
You've hit a bit of a sore spot with bookmarks. I was hoping Ryan
McElroy (hereby thrown under the bus) would be the one to submit some
patches in this direction but haven't seen any yet.
In my vision, 'hg up' without any argument should *not* move the
bookmark. It's another discussion as to where 'hg up' should go to in a
world with bookmarks.
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