merged two branches, and pushed, how to backout/strip?
Uwe Brauer
oub at mat.ucm.es
Mon Jan 9 23:07:09 UTC 2017
>>> "Arne" == Arne Babenhauserheide <arne_bab at web.de> writes:
>>
>> That is correct? However I end up in the vs-11.89 branch.
>>
>> I don't really understand
>> hg up vs-11.89
>> hg merge default
>> hg ci -m "merge default with the backout"
>> hg log -G
>> # revert the last bad commit to branch vs-11.89
>> hg revert --all -r 4
>> hg ci -m "backout the backout"
>>
>> Why are the merge and revert necessary?
> The merge and revert are necessary, because if you only revert the
> default branch, this branch then contains a commit which undoes all the
> work in vs-11.89. If you were to do some changes and then merge it into
> the vs-11.89 branch to get that branch up to date, it would undo all the
> work done in the vs-11.89 branch up until you first merged it into
> default.
> Reason: Default contains a change which undoes the changes in vs-11.89.
> To fix that, vs-11.89 needs a change which undoes the undoing of its
> changes.
Ok so I understand I have to move out the merge from both branches.
I thought
hg revert --all -r 1
hg commit -m "revert bad commit out of default branch"
hg up vs-11.89
hg revert --all -r 4
hg commit -m "revert bad commit out of vs-11.89 branch"
hg merge default
hg commit -m "Merge default into vs-11.89"
But this is not what you do.
I think I am too tired for that now. I have to think why you merge again
after the first revert before you backout.
Uwe
More information about the Mercurial
mailing list